7x^2-32x-15=(7x+3)

Solution for 7x^2-32x-15=(7x+3) equation:

7x^2-32x-15=(7x+3)

We move all terms to the left:

7x^2-32x-15-((7x+3))=0


We calculate terms in parentheses: -((7x+3)), so:

(7x+3)

We get rid of parentheses

7x+3

Back to the equation:

-(7x+3)


We get rid of parentheses

7x^2-32x-7x-3-15=0

We add all the numbers together, and all the variables

7x^2-39x-18=0

a = 7; b = -39; c = -18;
Δ = b2-4ac
Δ = -392-4·7·(-18)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-39)-45}{2*7}=\frac{-6}{14}
=-3/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-39)+45}{2*7}=\frac{84}{14}
=6
$